\documentclass[a4paper,10pt,french]{article}


\input macrodwicky.tex
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\begin{document}
\pagestyle{empty}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%	Cadre jaune
%\textbf{Nom : }$\dots\dots\dots\dots\dots$ \hfill \textbf{Pr\'enom : }$\dots\dots\dots\dots\dots$  \hfill Classe :$\dots\dots$\\
\psframebox[linestyle=solid,shadow=true,framearc=0.5,fillcolor=vert!30]{
\begin{minipage}{17cm}
\begin{center}
\vspace{1mm}
\textsc{\textbf{Correction de l'interrogation n$^{\circ}6$ }}
\end{center}
\vspace{-3mm}
\end{minipage}
}
\setcounter{section}{1}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%	 Interro
\Exoi{On considère un tétraèdre $ABCD$. $E$ et $F$ sont deux points de la face $BCD$ et $G$ est un point de la face $ACD$ :
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\psdots[dotsize=2pt 0,dotstyle=+](3.3,-1.51)
\rput[bl](3.39,-1.42){$L$}
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\end{center}
}


\Exoi{
\begin{enumerate}
\item 
\begin{itemize}
\item Les plans $(RON)$ et $(QPR)$ ont au moins un point commun $R$, ils sont donc sécants en une droite $\Delta$ qui passe par $R$.
\item La droite $(NO)$ est contenue dans le plan $(RON)$.
\item La droite $(QP)$ est contenue dans le plan $(QPR)$.
\item Les droites $(NO)$ et $(QP)$ sont parallèles.
\end{itemize}
Par conséquent d'après le théorème du toit la droite $\Delta // (NO)//(QP)$.
\end{enumerate}
Pour les autres questions, observer les constructions :
\begin{center}
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\end{center}
}
\newpage

\setcounter{Exi}{0}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%	Cadre jaune
%\textbf{Nom : }$\dots\dots\dots\dots\dots$ \hfill \textbf{Pr\'enom : }$\dots\dots\dots\dots\dots$  \hfill Classe :$\dots\dots$\\
\psframebox[linestyle=solid,shadow=true,framearc=0.5,fillcolor=vert!30]{
\begin{minipage}{17cm}
\begin{center}
\vspace{1mm}
\textsc{\textbf{Correction de l'interrogation n$^{\circ}6$ }}
\end{center}
\vspace{-3mm}
\end{minipage}
}

\Exoi{On considère un tétraèdre $ABCD$. $E$ et $F$ sont deux points de la face $BCD$ et $G$ est un point de la face $ACD$ :
\begin{center}
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\end{center}
}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%	 Interro bis
\Exoi{On considère un pavé droit $ABCDEFGH$, puis $I$ et $J$ deux points de la face $ABE$, et $K$ un point de la face $DCG$.
\begin{enumerate}
\item Les plans $(ABF)$ et $(DCG)$ sont parallèles, et le plan $(IJK)$ coupe $(ABF)$ selon la droite $(IJ)$, il coupe donc aussi $(DCG)$ selon une droite parallèle à $(IJ)$. $K$ étant un point de la face $DCG$, $(IJK)$ coupe $(DCG)$ selon une droite parallèle à $(IJ)$ qui passe par $K$.
\end{enumerate}
Observons les constructions sur la figure suivante :
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\end{document}
